could you help me pass a variable that was taken from a html form into javascript. The form asks for the tablename It is passed through PHP: A first action is underway, and created successfully: the Geoserver postgis table is created through PHP curl (entire code below) then the javascript tries to get $table with a PHP insert; this will
Tag: variables
How to fix the message “Undefined variable…” in WordPress [closed]
Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 11 months ago. Improve this question a problem suddenly occur on my website https://kcstravels.org I’ve this error message “Notice: Undefined variable: gLWHJ9848 in /home/kcstra3473/public_html/wp-content/themes/sketch/404.php on line 1” on the top and
Function echos variable correctly to ajax file but in html doesn’t show anything
Php variable $testing correctly echos ajax file, but in html <?php echo $testing;?> doesn’t show anything. html: functions.php: Answer The solution is to add $(‘#featured-image’).html(data); to the script, which pass the data output to html. also moved php lines from html to function.php: I missunderstood how ajax works. The simplest answer imo is this diagram:
laravel – Can I add new items to an array that already has some existing items?
var_export($response) is an array like below: The below code gives a result like this: “data”: 3. I wanted add a new item called points with the $response array, into all elements. But here, it overwrites the existing array. How can I achieve this? Expected output: Answer As mentioned, array_push() returns the new number of elements in the array. That’s why
How to Use an Outside Variable Inside a For Loop (Scope)
Simple question that I haven’t seen answered anywhere: How can I use an outside $variable, inside a for loop? In my PHP code, I have a SplDoubleyLinkedList full of friends names, and I am looping through them one by one to use in an if statement that compares the current friend to the $friend name parameter. How can I change
How can I give an html element an ID taken from a php variable?
I am creating a website which uses php to get data from a phpmyadmin database and use the info from this database in my html. I have this php query which finds the value from the ‘ID’ field and then creates a variable called ‘$studentID’ with this value (which will be the number 2 in this case): Then I have
How Can I Identify Which Linked Was Clicked With PHP?
I have connected to my database with PHP and selected a bunch of names with a query. Each name has an id value. I created a while loop that loops through the results and outputs something like this: (id only displayed for explanation purposes) At the linked page I want to run a query like SELECT * FROM database.table WHERE
How to calculate the age of a person using variables like: year, month, day in PHP
I have tried to get the age of a person, using the code below, although I wanted the output to be your exact age, it reads an incorrect age if your birthday was before the current date but a correct age if your birthday is after the current date kindly correct the code Answer You can use this for age
I’m having a problem with codeigniter pagination
When I create pagination without category it works, but with the category, it works with wrong data. With category pagination, it should show the data of a single category. But unfortunately, it shows mixed category data. These things work fine on the Index function….. In my index controller… and my model for the index is … It works perfectly. But
How to parse Minecraft ops.json to display all oped users, their UUID’s and the total amount of oped users
Sorry if the title of this doesn’t make sense, I’m very new to working with JSON files in PHP. I looked almost everywhere and reworded my question multiple times, every answer I get doesn’t seem to work my JSON file, not sure if Minecraft does something different or if I’m missing something. Thank you to anyone who responds to this!