Is there any way that if I have a command of this kind: To call it without specifying arg4, but with arg5? Something like: Of course, if I do it like above arg5_val will be interpreted like arg4_val and arg5 will be ignored. I hope my question is clear and it was not answered already. Did not even have a
Tag: arguments
Android passing username to php
I am building an android app where the users are expected to perform certain tasks individually assigned to them. To download the project information I am using HTTPServiceClass and passing in a url …
PHP optional parameter
I’m kinda confused about optional parameters, or setting a parameter within the function in general. So I found this example:
Sort results from high to low float array – wordpress
Maybe this should be very easy but I am a bit lost on how to sort this data in a good way. I got this query in a WordPress template to get some post_meta: $args = array( …
Using Default Arguments in a Function
I am confused about default values for PHP functions. Say I have a function like this: What if I want to use the default argument for $x and set a different argument for $y? I have been experimenting with different ways and I am just getting more confused. For example, I tried these two: But both of those do not