PHP Generate day range

I am trying to generate the range of days, from 1 to 28, with the English ordinal suffix for the day of the month. For example: 1st of month, 2nd of month…

for($i = 1; $i <= 28; $i++)
{
    $arrayRange[] = date('dS', strtotime($i));
}

echo "<pre>";
print_r($arrayRange);
echo "</pre>";

Output:

Array
(
    [0] => 01st
    [1] => 01st
    [2] => 01st
    ...
    [26] => 01st
    [27] => 01st
)

What am I doing wrong..?

Answer

Try this, it uses the contextual date functionality of ‘+1 day’ etc to register your integer as a day 🙂

To answer your second question – as in what you’re doing wrong – you’re passing an integer to a function that expects a string.

<?php
for($i = 0; $i <= 27; $i++)
{
//The February is there to keep '1st' a '1st' even on days when it's not 
//the '31st'
$arrayRange[] = date('dS', strtotime("1st february +".$i.' day'));
}

echo "<pre>";
print_r($arrayRange);
echo "</pre>";

Output:

Array
(
    [0] => 01st
    [1] => 02nd
    ...
    [28] => 28th
)¨

Edit:
To remove the 0s, you can use ltrim() like this:

$arrayRange[$i] = ltrim(date('dS', strtotime("1st february +".$i.' day')), "0");

Which will give you an output like this

    [0] => 1st
    [1] => 2nd
    ...
    [28] => 28th

Edit 2: Fixed it. Props to MLF for noticing the mistake.