I am trying to filter an array
JavaScript
x
$array = [
[
'id' => 1,
'some_key' => 'some_value',
'attribute' => [
'id' => 45,
'cat_id' => 1
],
'sub' => [
'id' => 17,
'some_key' => 'some_value',
'attribute' => [
'id' => 47,
'cat_id' => 17
],
],
],
[
'id' => 2,
'some_key' => 'some_value',
'sub' => [
'id' => 19,
'some_key' => 'some_value',
],
]
];
$childArray = [];
array_walk_recursive($array, static function($value, $key) use(&$childArray){
if($key === 'id') {
$childArray[] = $value;
}
});
This returns me an array of all array-fields having id
as key.
JavaScript
[1,45,17,47,2,19]
But there is a small problem, some of the array have an key called attribute
containing an id
key field that I dont want to have.
JavaScript
[1,17,2,19] //this is what I want
Is there a way to say “don’t take the id inside attribute” ?
My current solution, I added a filter before my filter 😀
JavaScript
/**
* @param array $array
* @param string $unwanted_key
*/
private function recursive_unset(&$array, $unwanted_key)
{
unset($array[$unwanted_key]);
foreach ($array as &$value) {
if (is_array($value)) {
$this->recursive_unset($value, $unwanted_key);
}
}
}
but this seems like this is not the best practice ^^
Advertisement
Answer
You can traverse recursively manually instead of array_walk_recursive
and avoid all under attribute
key.
JavaScript
<?php
$childArray = [];
function collectIDs($arr,&$childArray){
foreach($arr as $key => $value){
if($key === 'attribute') continue;
if(is_array($value)) collectIDs($value,$childArray);
else if($key === 'id') $childArray[] = $value;
}
}
collectIDs($array,$childArray);
print_r($childArray);
Demo: https://3v4l.org/V6uFf