I am working on this site that follow and unfollow users just like Twitter follow. The query below works then I notice it doesn’t show me users I don’t follow because the user has been followed by somebody or is following somebody
$stmt = $mysqli->prepare("SELECT * FROM town_users LEFT JOIN user_follow_list ON user_follow_list.following_id = town_users.user_id WHERE town_users.user_id != ? AND user_follow_list.follow_id IS NULL ORDER BY RAND() LIMIT 5");
$stmt->bind_param("i", $user_id);
Below is my table structure
town_users user_id username | 1 | ben | 2 | betty | 3 | tom | 4 | john user_follow_list follow_id follower_id following_id | 1 | 1 | 2 | 2 | 1 | 3
In the user_follow_list Ben is following betty and tom. Now john follows a user let say tom,
follow_id follower_id following_id | 3 | 4 | 3
Now the problem am having is that john doesn’t show up on ben list of users to follow.
It’s meant to show users I haven’t followed so I can follow them.
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Answer
SELECT * FROM town_users LEFT JOIN user_follow_list ON user_follow_list.follower_id = town_users.user_id WHERE town_users.user_id NOT IN (SELECT following_id FROM user_follow_list WHERE follower_id = 1) AND town_users.user_id != 1 GROUP BY town_users.user_id ORDER BY RAND() LIMIT 5
This query will get all the user that are not being followed by ($user_id = 1).
$stmt = $mysqli->prepare("SELECT * FROM town_users
LEFT JOIN user_follow_list ON user_follow_list.follower_id = town_users.user_id
WHERE town_users.user_id NOT IN (SELECT following_id FROM user_follow_list WHERE follower_id = ?)
AND town_users.user_id != ?
GROUP BY town_users.user_id ORDER BY RAND() LIMIT 5");
$stmt->bind_param("ii", $user_id, $user_id);
Here’s a SQL Fiddle: http://sqlfiddle.com/#!9/96d55/23/0