I’m trying to fetch data from the database using Xamp Server but am getting this error.
Fatal error: Uncaught Error: Call to undefined function mysql_select_db() in E:xamphtdocsPoliceAppNewsfetch.php:10 Stack trace: #0 {main} thrown in E:xamphtdocsPoliceAppNewsfetch.php on line 10
Below is my php script , am still new in php please help me out on this. But i read all the other Posts here but it seems it’s confusing to me,how can I make it right please.
JavaScript
x
<?php
$username="root";
$password="namungoona";
$hostname = "localhost";
//connection string with database
$dbhandle = mysqli_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "";
// connect with database
$selected = mysql_select_db("police",$dbhandle)
or die("Could not select examples");
//query fire
$result = mysql_query("select * from News;");
$json_response = array();
// fetch data in array format
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
// Fetch data of Fname Column and store in array of row_array
$row_array['Headlines'] = $row['Headlines'];
$row_array['Details'] = $row['Details'];
$row_array['NewsPhoto'] = $row['NewsPhoto'];
//push the values in the array
array_push($json_response,$row_array);
}
//
echo json_encode($json_response);
?>
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Answer
As per your request i have modified code.
JavaScript
<?php
$username="root";
$password="namungoona";
$hostname = "localhost";
//connection string with database
$dbhandle = mysqli_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "";
// connect with database
$selected = mysqli_select_db($dbhandle, "police")
or die("Could not select examples");
//query fire
$result = mysqli_query($dbhandle,"select * from News;");
$json_response = array();
// fetch data in array format
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
// Fetch data of Fname Column and store in array of row_array
$row_array['Headlines'] = $row['Headlines'];
$row_array['Details'] = $row['Details'];
$row_array['NewsPhoto'] = $row['NewsPhoto'];
//push the values in the array
array_push($json_response,$row_array);
}
//
echo json_encode($json_response);
mysqli_free_result($result);
?>
Please note: you need to add error checking. Also note just typed in here (not tested), so bear with me if there are some errors.