I’ve written some code in my PHP snippet which is on my WordPress page and the wpdb query gives me always a wrong result. In WordPress In SQL phpmyadmin displayed 3 which is the correct result for that query What did I do wrong? May you help me in someway? Answer The reason why you’re getting 1 as a result
Tag: sql
Laravel controller shows syntax error, unexpected variable “$user”, expecting “function” or “const”
I am creating a forgot password feature in my application and when creating my controller, I used this code: But the first line gives an syntax error, unexpected variable “$user”, expecting “function” or “const” error. Does anyone know what I am doing wrong? Answer Make Sure Your { } are correct..and the code inside a function,check ; are correct
how to create Dynamic Input value with two different datatype time and text and insert into one single column
I have Dynamic Input box with Time Input and Text Input I want to show as a list items and also wanted to insert values in one column of table in SQL example : 09.30 PM Saturday night journey begins. 01.30 AM We Reach the Base village 02:00 AM Some Yumm, Breakfast! How to add multiple input for list item
How to show only those sellers who have created at-least one product
I have one sellers table where sellerid column is sno and I have products table where sellerid is sellerid , I want to get those sellers who are not blocked (there is column named flag in sellers table) and have created at least one product so I write this(or maybe copy this) Now I do my logic through: It is
utf8_encode difference between result in SQL and PHP
I’m using utf8_encode to make sure that the input from my users is transforming the special characters to a character where my MYSQL can do a search on. (My database is set in latin1_swedish.ci). When I echo my query, I get a perfect query that I can run against my MYSQL (and I get an result). But when I do
Sum of amount for each date having ‘type’ column in sql
I have table expense_incomes, the structure for table is: I want the sum of expenses and incomes in two different arrays groupBy date. I have tried this code. (In the above Example) I want to push expense into expense_array and income into income_array for 2021-04-02. What I am getting now: Expected Array Structure: Answer I believe you want an aggregated
Import values from temporary table to another table?
I’m joining 3 tables: Currently, I’m fetching the data, build a new array and insert it into my final table. However, I wonder if it’s possible to do this in one go, so basically directly from the temporary table? Answer Yes. Use INSERT . . . SELECT: Note that I introduced table aliases. These make the query easier to write
“a symbol name was expected” error trying to create a table in phpMyAdmin
I am trying to create a table in a database in phpMyAdmin and I keep getting the “a symbol name was expected” error and I cannot figure out what is going on. Is my syntax wrong? I am new to this and I’m at a loss. Answer Column names, table names should be surrounded by backticks(“) Or you can go
How do I assign different variables for an SQL result that is joined
I am working on a project and I came across something that I just don’t know how to solve. I have 3 tables in a Firebird database : Team 1 – jumping The player 10 and 15 are in Team 1 And the last table is this one : Player 10 -> Alex -> age 25 -> height 175 Player
Why would SQL update the date into tabel to 0000-00-00 00:00:00?
I am trying to update the field SEEN in a SQL table to the current time and date. Here is the code: It sets my SEEN field to 0000-00-00 00:00:00. If I write a specific date directly into the query, say “2021-03-10 02:30:00” it would write that date into the SEEN field. But instead of $now, it would output 0s.