I have read from some posts that it is a better practice to execute queries one by one instead of doing the multi-query function in PHP files. I wonder say I have two mysqli_query functions, is it possible that the first query succeeds and MySQL Database has been changed accordingly when the next query fails? If this is the case,
Tag: mysqli
Fetch array data from one table and insert into another table
I want to fetch array data from “orders” Table WHERE order_id =2 and insert into “inventory_log” Table. but my code is only inserting the last row orders TABLE I want this: inventory_log TABLE Find my code below: Answer It is only inserting one row because you are only posting 1 product_id and 1 quantity your posted data in php now
mysqli query inside foreach loop- syntax problem
I have the following mysqli query: This is my database table “items”: $response is an API array from where I get the value for the item_ids . I get the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ” at line
How can I convert this mysqli to PDO?
prepare(“SELECT * FROM userinfo order by id DESC”); $query->execute(); mysqli_stmt_bind_result($…
How to user fetch_assoc() twice in a single php file?
I have two table. One is an article list and the other one is a category list. In the category table, I have use fetch_assoc() to get the data from my DB and list in the table. But I want to fetch the …
How do i store / serialize php returned mysqli_query results?
I’m trying to store results returned from mysqli_query as cache, so if the same “SELECT” statement is executed, it will get from the cache instead of going through mysql server BUT the …
convert mysql to mysqli procedural way for google charts
I am trying to upgrade some google charts i use for my own use from mysql to mysqli procedural way, and i have trouble in re-creating the correct array for the google chart to understand. I think i am …
PHP: mysqli_stmt->close() affecting earlier copy of stmt
I am making a function to more easily use prepared statements in sql queries. But while working on it, I ran into a strange bug. When you run the code below the first var_dump of $response prints the $…
User updated information not showing
i have problem in my php which is user updated data is not showing in the page, it shows only the previous data and not the updated data, but the information already updated in database This is my updateForm.php: This is my stdUpdateData.php, where the sql database process the update data: This is the studentProfile.php,when user register for the first
Isn’t needed calling the mysqli function to insert values?
I am learning MySQL and PHP, I have seen that with this code you can insert values in the database: So like you see, this should work, but I don’t get how. If you are never calling the function mysqli_query, it is just stored in the $insert variable. It’s called in the if condition? Another thing that called my attention