I need to create a form with 5 fields in which a number will be entered in each, clicking a button a query is performed out based on the values entered in the fields and display the results within an html page. Thanks. Answer I achieved what I was looking for with the following: The form and javascript: Result and
Tag: html
How can I add alert button to the radio option if I have multiple select tags with same option?
Note: Multiple select tags were added using for loop in PHP.The problem I am facing is when I have multiple select tags with same options I could not know which select is calling selectfun() <?php Answer you can use pass parameter from the click event, here you can read more about how to pass the parameter from the functions in
How to insert 3 image to 3 field in DB Laravel
I want to insert 3 images to 3 fields in DB, but I can’t move this to folder public. My code in function store in Controller Someone help me. Thank you. Answer Try this:
Change dates in fixed link and execute link
I have link like this: http://xyz.zxy.com/getTRZ/?id=BB195E05&dateFrom=03.11.2020&dateTO=03.11.2020 How to create a form with two input date fields and combine them into one link like one above? I want to pick dateFrom and dateTo separately and click GO to visit the link. Is that possible to create in HTML? I would like to put it in my bookmark because I use the
PHP: how to correct if else statement to check if POST array is empty or not, and if not check REGEX to continue
I’m working on an e-commerce website project, and I’m trying to validate customer’s information using PHP. And I’m here trying to check if the customer put his/her phone number, and to check if the …
Laravel how to register a user with a default image in user::create
I wanted to make it that when you register a new user it comes with a default picture : https://upload.wikimedia.org/wikipedia/commons/8/89/Portrait_Placeholder.png I tried something like this but it …
JQuery fails to load when i use a php variable
I’m incorporating PHP code into JQuery like this: The PHP variable shows as blue, there are no errors showing, but when I run it it refuses to work. I’ve tested everything else and I’m 100% sure PHP is the one causing the problem. How can I fix this? Answer If $c is your php variable you will need to quote
PHP MYSQL Results into a table
I have a PHP/MySQL query that returns the following: The months return in an ordered fashion (E.g. January records are always before February records). However, not every user will have a result every month (see above). And I want my data to present such as this, in an html table: Here is my (non working) attempt: Which unfortunately results in
Sending Data from PHP to Javascript to PHP
I don’t understand how to explain my question, but I’m trying to say what I wanted to do. I have created a modal to submit ‘payment’ for each person. I have created the list of person in a table with PHP loop, and a button against each person so that payment can be done by clicking the button. When I
Update the data of an existing table in PHP
I need to make a table of searches made by the user in php. My code fails to encapsulate every new result in the table. I’d like you not to create a new table every time and delete the data, but to gradually add to the data already in the table. Also I have a problem with highlighting accents or