I am calling an API from where I am getting date /Date(1365004652303-0500)/
, I don’t understand what format this is. How is this date format called? I was not sure what to google for such type of format.
Can anyone help me out in getting this date in Y-m-d H:i:s
format?
The API I am calling is on .NET server. And when I call it using PHP’s file_get_contents
and json_decode
it gives me the following Date format for created date: /Date(1365004652303-0500)/
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Answer
First you need to understand the format you have
/Date(1365004652303-0500)/
Then you have
- time stamp (U) = 1365004652
- Milliseconds (u) = 303
- Difference to Greenwich time (GMT) (O) = -0500
Build a Format
$date = '/Date(1365004652303-0500)/'; preg_match('/(d{10})(d{3})([+-]d{4})/', $date, $matches); $dt = DateTime::createFromFormat("U.u.O",vsprintf('%2$s.%3$s.%4$s', $matches)); echo $dt->format('r');
Output
Wed, 03 Apr 2013 15:57:32 -0500 ^ |= Can you see the GMT ?
interface DateFormatParser { /** * @param $string * * @return DateTime */ public function parse($string); } abstract class PregDateParser implements DateFormatParser { protected $pattern, $format, $mask; public function parse($string) { $string = (string)$string; $pattern = $this->pattern; $format = $this->format; $mask = $this->mask; $r = preg_match($pattern, $string, $matches); if (!$r) { throw new UnexpectedValueException('Preg Regex Pattern failed.'); } $buffer = vsprintf($mask, $matches); $result = DateTime::createFromFormat($format, $buffer); if (!$result) { throw new UnexpectedValueException(sprintf('Failed To Create from Format "%s" for "%s".', $format, $buffer)); } return $result; } } class JsonTimestampWithOffsetParser extends PregDateParser { protected $pattern = '/^/Date((d{10})(d{3})([+-]d{4}))/$/'; protected $format = 'U.u.O'; protected $mask = '%2$s.%3$s.%4$s'; } $date = '/Date(1365004652303-0500)/'; $parser = new JsonTimestampWithOffsetParser; $dt = $parser->parse($date); echo $dt->format('r');