I am calling an API from where I am getting date /Date(1365004652303-0500)/, I don’t understand what format this is. How is this date format called? I was not sure what to google for such type of format.
Can anyone help me out in getting this date in Y-m-d H:i:s format?
The API I am calling is on .NET server. And when I call it using PHP’s file_get_contents and json_decode it gives me the following Date format for created date: /Date(1365004652303-0500)/
Advertisement
Answer
First you need to understand the format you have
/Date(1365004652303-0500)/
Then you have
- time stamp (U) = 1365004652
- Milliseconds (u) = 303
- Difference to Greenwich time (GMT) (O) = -0500
Build a Format
$date = '/Date(1365004652303-0500)/';
preg_match('/(d{10})(d{3})([+-]d{4})/', $date, $matches);
$dt = DateTime::createFromFormat("U.u.O",vsprintf('%2$s.%3$s.%4$s', $matches));
echo $dt->format('r');
Output
Wed, 03 Apr 2013 15:57:32 -0500
^
|= Can you see the GMT ?
interface DateFormatParser
{
/**
* @param $string
*
* @return DateTime
*/
public function parse($string);
}
abstract class PregDateParser implements DateFormatParser
{
protected $pattern, $format, $mask;
public function parse($string) {
$string = (string)$string;
$pattern = $this->pattern;
$format = $this->format;
$mask = $this->mask;
$r = preg_match($pattern, $string, $matches);
if (!$r) {
throw new UnexpectedValueException('Preg Regex Pattern failed.');
}
$buffer = vsprintf($mask, $matches);
$result = DateTime::createFromFormat($format, $buffer);
if (!$result) {
throw new UnexpectedValueException(sprintf('Failed To Create from Format "%s" for "%s".', $format, $buffer));
}
return $result;
}
}
class JsonTimestampWithOffsetParser extends PregDateParser
{
protected $pattern = '/^/Date((d{10})(d{3})([+-]d{4}))/$/';
protected $format = 'U.u.O';
protected $mask = '%2$s.%3$s.%4$s';
}
$date = '/Date(1365004652303-0500)/';
$parser = new JsonTimestampWithOffsetParser;
$dt = $parser->parse($date);
echo $dt->format('r');