I’m doing this (yes, I’m using wrong connection data, it’s to force a connection error )
JavaScript
x
try {
$connection = new mysqli('localhost', 'my_user', 'my_password', 'my_db') ;
} catch (Exception $e ) {
echo "Service unavailable";
exit (3);
}
But PHP is doing this php_warning:
mysqli::mysqli(): (28000/1045): Access denied for user ‘my_user’@’localhost’ (using password: YES)
In the example I’m using wrong connection data to force a connection error, but in the real world the database could be down, or the network could be down… etc..
Question: Is there a way, without suppressing warnings, to intercept a problem with the database connection ?
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Answer
You need to tell mysqli to throw exceptions:
JavaScript
mysqli_report(MYSQLI_REPORT_STRICT);
try {
$connection = new mysqli('localhost', 'my_user', 'my_password', 'my_db') ;
} catch (Exception $e ) {
echo "Service unavailable";
echo "message: " . $e->message; // not in live code obviously...
exit;
}
Now you will catch the exception and you can take it from there.