I am getting the following error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ” at line 114
but my code is only 27 lines long
JavaScript
x
<?php
$DB_NAME = 'QCSYSTEM';
$DB_HOST = 'monitor';
$DB_USER = 'QCSYSTEM';
$DB_PASS = '247#Direct';
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if (mysqli_connect_errno()) {
printf("Connect failed: %sn", mysqli_connect_error());
exit();
}
// A QUICK QUERY ON A FAKE USER TABLE
$query = "SELECT username FROM `users` WHERE";
$result = $mysqli->query($query) or die($mysqli->error.__LINE__);
// GOING THROUGH THE DATA
if($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo stripslashes($row['username']);
}
}
else {
echo 'NO RESULTS';
}
// CLOSE CONNECTION
mysqli_close($mysqli);
?>
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Answer
You are missing to state your WHERE
clause here
JavaScript
$query = "SELECT username FROM `users` WHERE";
Either remove it
JavaScript
$query = "SELECT username FROM `users`";
or apply any clause
JavaScript
$query = "SELECT username FROM `users` WHERE column = 'something'";