In file A,
Class A {
__construct() {
...
lots of code
...
}
public function P() {
code here
}
}
New A();
In file B,
Class B {
__construct() {
...
lots of code
...
}
public function E() {
I need to call function P in Class A
}
}
New B();
I would like to call the function P() in function E().
Is there any way to call a function in another class?
I found several ways such as dependency injection using __construct( A $aobj ) or “extends”
However, the class A was already instantiated in file A and there’re a lot of things in __counstruct so I would like to know
1) the way of refractory technique
2) fancy way to call function E() in function P().
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Answer
It really depends on how class B is related to A :
no link : the function in A should be static (it doesn’t interact with a specific instance of
Aand its properties), and you can callA::P()the class B is a child of A :
In B class definition, you have a class B extends A and in the constructor of B, you will have a parent::__construct() to call the constructor of A.
Then you can simply call $this->P() : as B is a subclass of A, and P is public (or protected), B inherits of all methods from A
- The class B uses a object of type A`
Then, you must have a $a attribute in the class B, and a $this->a = new A(); in the constructor of B. You can call P with $this->a->P();
Or if you need only temporarily A in E(), you can construct a new object $a = new A(); and call $a->P(); in the code of E