I am creating a new array in a for loop.
for $i < $number_of_items $data[$i] = $some_data;
PHP keeps complaining about the offset since for each iteration I add a new index for the array, which is kind of stupid.
Notice: Undefined offset: 1 in include() (line 23 of /... Notice: Undefined offset: 1 in include() (line 23 of /.. Notice: Undefined offset: 1 in include() (line 23 of /..
Is there some way to predefine the number items in the array so that PHP will not show this notice?
In other words, can I predefine the size of the array in a similar way to this?
$myarray = array($size_of_the_earray);
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Answer
There is no way to create an array of a predefined size without also supplying values for the elements of that array.
The best way to initialize an array like that is array_fill
. By far preferable over the various loop-and-insert solutions.
$my_array = array_fill(0, $size_of_the_array, $some_data);
Every position in the $my_array
will contain $some_data
.
The first zero in array_fill
just indicates the index from where the array needs to be filled with the value.