I’m getting the data I need from fgetcsv
and store them into $data
. It contains a table with a header row and lot’s of info. Every 7th column is the path to where the file is stored.
I’ve already searched for what my problem is but I can’t seem the find the solution.
My Code yet:
echo '<table border="0" cellspacing="0" cellpadding="5" class="csvTable" width="auto">'; $handle = fopen("index.csv", "r"); $start = 0; while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) { echo '<tr>' . "n"; for ( $x = 0; $x < count($data); $x++) { if ($start == 0 && $hasTitle == true) echo '<th>'.$data[$x].'</th>' . "n"; else echo '<td>'.$data[$x].'</td>' . "n"; } $start++; echo '</tr>' . "n"; } fclose($handle); echo '</table>';
I want to add a hyperlink via <a href=?>
on every 7th column but I don’t know how. How can I do it and is that the right way?
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Answer
You check every column is a 7th column or divisible by 7 you can just check if the variable is divided by 7 like this.
echo '<table border="0" cellspacing="0" cellpadding="5" class="csvTable" width="auto">'; $handle = fopen("index.csv", "r"); $start = 0; while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) { echo '<tr>' . "n"; for ( $x = 0; $x < count($data); $x++) { if ($start == 0 && $hasTitle == true) echo '<th>'.$data[$x].'</th>' . "n"; else echo '<td>'.$data[$x].'</td>' . "n"; if( $x && !($x % 7) ){ echo '<a href=?>' } } $start++; echo '</tr>' . "n"; } fclose($handle); echo '</table>';