FTP upload via PHP form

I want to upload a file via FTP upload in a form.

<html>
  <body>
    <form enctype="multipart/form-data" action="upload_file.php" method="POST">
      <input type="hidden" name="MAX_FILE_SIZE" value="100000" />
      Choose a file to upload: <input name="uploadedfile" type="file" /><br />
      <input type="submit" value="Upload File" />
    </form>
  </body>
</html>

JavaScript
​x
 
<html>  <body>    <form enctype="multipart/form-data" action="upload_file.php" method="POST">      <input type="hidden" name="MAX_FILE_SIZE" value="100000" />      Choose a file to upload: <input name="uploadedfile" type="file" /><br />      <input type="submit" value="Upload File" />    </form>  </body></html>​

Here is the PHP file:

<?php

$ftp_server = "xxx";
$ftp_username   = "xxx";
$ftp_password   =  "xxx";

// setup of connection
$conn_id = ftp_connect($ftp_server) or die("could not connect to $ftp_server");

// login
if (@ftp_login($conn_id, $ftp_username, $ftp_password))
{
  echo "conectd as $ftp_username@$ftp_servern";
}
else
{
  echo "could not connect as $ftp_usernamen";
}

$file = $_FILES["file"]["name"];
$remote_file_path = "/home/www/lifestyle69/import/".$file;
ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII);
ftp_close($conn_id);
echo "nnconnection closed";

?>

JavaScript
 
<?php​$ftp_server = "xxx";$ftp_username   = "xxx";$ftp_password   =  "xxx";​// setup of connection$conn_id = ftp_connect($ftp_server) or die("could not connect to $ftp_server");​// loginif (@ftp_login($conn_id, $ftp_username, $ftp_password)){  echo "conectd as $ftp_username@$ftp_servern";}else{  echo "could not connect as $ftp_usernamen";}​$file = $_FILES["file"]["name"];$remote_file_path = "/home/www/lifestyle69/import/".$file;ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII);ftp_close($conn_id);echo "nnconnection closed";​?>​

The FTP connection connects successfully but the file is nowhere.

Can anybody help me?

Thanks!

Answer

Because you have <input name="uploadedfile" type="file" />:

$file = $_FILES["file"]["name"]; // wrong
$file = $_FILES["uploadedfile"]["name"]; // right

JavaScript
 
$file = $_FILES["file"]["name"]; // wrong$file = $_FILES["uploadedfile"]["name"]; // right​

Because you need the filename of the temporary copy stored by PHP, which exists on the server:

ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII); // wrong
ftp_put($conn_id, $remote_file_path, $_FILES["uploadedfile"]["tmp_name"],
        FTP_ASCII); // right

JavaScript
 
ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII); // wrongftp_put($conn_id, $remote_file_path, $_FILES["uploadedfile"]["tmp_name"],        FTP_ASCII); // right​

Refer to the PHP documentation for more information about $_FILES.

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Answer