Detect the right name in string

So I was wondering how to detect the right files, by their names, when I scan through them.

Right now when I open a pop-up window, I GET a id (?id=2451961), and this id is used to detect image files in a folder. But how should i detect them?

Is there a way to say, the start of the files name to the first non-number should be the id, and if it’s equal to the id then thats one of the files?

The folder with some files could be this:

Right now I loop through the files like this, but it doesn’t get the file '2451961 - Copy.png':

foreach ($list as $file) {
    $file_name = strtolower(substr(strtok($file, '.'),0));
    $type = strtolower(substr(strrchr($file,"."),1));
    if ($type != "log" ) {
        if ((strtok($file, '_') == $id) || $file_name == $id) {
            $scr = '../test/ftp_image.php?img='.$file;
            ?>
            <img src="<?php echo $scr; ?>" height="250px"/> <?php

            echo $file;
        }
    }
}

Note: there is a statement exclude = .log files in the code, which is because there is some files containing text which shouldn’t be takes into consideration.

The files i want to get in this example is these:

NOTE: Not all images will be .png, there could be a .jpg or something like that.

file names:

2451961 - Copy.png
2451961.jpg
2451961 - Copy 2.png
2451961 - Copy_2.jpeg

Answer

Regex looks like a better/right tool for this job. Your regex could look like below:

'/^'.preg_quote($id).'D/'

preg_quote is just for escaping of any regex metacharacters. So, your file name should start with the ID followed by a non digit, which is D. We won’t have to care about file extensions if we do it this way.

Snippet:

<?php

$files = [
    '2451961 - Copy.png',
    '2451961.png',
    '2451961_2 - Copy.png',
    '2451961_2.png',
    '4405.png'
];

$id = '2451961';

foreach($files as $file){
    echo $file, " ", var_dump(preg_match('/^'.preg_quote($id).'D/', $file) === 1),PHP_EOL;
}

Online Demo