I am trying to convert CSV file to JSON using PHP.
Here is my code
<?php date_default_timezone_set('UTC'); $today = date("n_j"); // Today is 1/23/2015 -> $today = 1_23 $file_name = $today.'.CSV'; // My file name is 1_23.csv $file_path = 'C:\Users\bheng\Desktop\qb\'.$file_name; $file_handle = fopen($file_path, "r"); $result = array(); if ($file_handle !== FALSE) { $column_headers = fgetcsv($file_handle); foreach($column_headers as $header) { $result[$header] = array(); } while (($data = fgetcsv($file_handle)) !== FALSE) { $i = 0; foreach($result as &$column) { $column[] = $data[$i++]; } } fclose($file_handle); } // print_r($result); // I see all data(s) except the header $json = json_encode($result); echo $json; ?>
print_r($result);
// I see all data(s)
Then I json_encode($result);
and tried to display it, but nothing is displaying on the screen at all. All I see is the blank screen, and 0 error message.
Am I doing anything wrong ? Can someone help me ?
Added Result of
print_r($result);
Array ( [Inventory] => Array ( [0] => bs-0468R(20ug) [1] => bs-1338R(1ml) [2] => bs-1557G(no bsa) [3] => bs-3295R(no BSA) [4] => bs-0730R-Cy5" [5] => bs-3889R-PE-Cy7" [6] => 11033R [7] => 1554R-A647 [8] => 4667 [9] => ABIN731018 [10] => Anti-DBNL protein .... more ....
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Answer
Try like this:
$file="1_23.csv"; $csv= file_get_contents($file); $array = array_map("str_getcsv", explode("n", $csv)); $json = json_encode($array); print_r($json);