Regexp: find all occurences on same string inside brackets

i already few days trying write some regexp for replacing all : inside brackets, pls help me, so i have string:

render('MyBundle:Default:index.html.twig')
or render('MyBundle::Default::index.html.twig')

how i can get all : and replace it with / ? i trying something like:

render(.*([:])

but it’s find only last :

Answer

In a general case, it will look like

(?:G(?!^)|render(')[^':]*K:+

See the regex demo. Remove the last + if you need to replace each : with a /.

Details:

• (?:G(?!^)|render(') – render(' or the end of the previous match
• [^':]* – zero or more chars other than ' and :
• K – match reset operator that discards the text matched so far
• :+ – (the only text that is finally put into the match value and eventually replaced) one or more colons.