Using $.each loop to create multiple divs, not wor…

I’ve got a php page setup as follows:

<?php
    if(isset($_POST['submit'])){
        // Validate results and if correct insert into the DB
        // Else add the respective errors
        $data[0]['error_1'] = 'Error_1_text';
        $data[0]['error_2'] = 'Error_2_text';
        /*
        .
        .
        .
        */
        $data[0]['error_n'] = 'Error_n_text';
        print_r(json_encode($data[0]));
    }
?>

This is where the following AJAX request sends a POST request. If the entered form is valid it is inserted into DB else if it has any error(s) all the errors are appended to the array index $data[0], and finally the array is json_encoded, and print_r()ed.

<body>
    <div class="ssss"></div>
</body>
<script>
    $.ajax({
        url: "http://localhost/path/to/above/file",
        method: "POST",
        data: {
            submit: 'yes',
            form_data_0: 'form_text',
            form_data_1: 'form_text',
            form_data_2: 'form_text'
        },
        success: function(data){
            // Code to check if errors were present
            result = JSON.parse(data);
            if (result.hasOwnProperty('0')) {
                $.each(result['0'], function(key, error) {
                    let x = 0;
                    // Display each error into a modal
                    $("div#ssss").html('<div id="dmessage_' + x + '" class = "modal" style="display:block"><p id = "pmessage_' + x + '">' + error + '</p></div>');
                    x++;
                });
            }
        }
    });
</script>

On success of the AJAX request, the data is JSON.parse()d and this result is assigned to a variable result. Then we check if there were any errors during the post-processing of the form. using if (result.hasOwnProperty('0')), if so, the aim is to display each error in a <p>error</p> with a dynamic id enveloped in a <div> with a dynamic id.
To achieve this I created a $.each() loop and initiated a variable x = 0. Now we loop over the contents of the $.each() loop, where we intend to display a <div></div> with contents shown in the code along with the error text being sent over by PHP from the back-end and the id being dmessage_ concatenated with the current value of x. Once done, we increment x and loop over again for the next error.
However what happens is, only 1 error-box is displayed, no-matter how many errors are being sent by PHP. I confirmed that by adding the following piece of code inside the if() statement:

let array = [];
$.each(result['0'], function(key, error) {
    // Display each error into a modal
});
array[x] = array.push(error);
console.log(array); // Displays all the errors correctly inside the console

Also thing worth noting is that although only one error-box is displayed all are created for each error. I confirmed that by console.log()ging $().html() this piece of code,
however the elements tab in developer tools along with the browser display window shows only one error-box.

Answer

^{I know you got a solution but I will post my answer}

1st: echo json_encode

2nd: You return $data[0] from PHP .. that mean the array will looks like

['error_1' => 'Error_1_text' , 'error_2' => 'Error_2_text' , ......]

3rd: On success function You loop through result[0] which will be in this case = 'error_1' => 'Error_1_text'

4th: No need to use x at all you can directly use key

5th: You can directly use dataType: 'json' instead of JSON.parse(data)

6th: change .html( to .append(

Consider all of the above then your code should looks like

php

<?php
    if(isset($_POST['submit'])){
        // Validate results and if correct insert into the DB
        // Else add the respective errors
        $data['error']['error_1'] = 'Error_1_text'; // change all `$data[0]` to `$data['error']` it will be much easier 
        $data['error']['error_2'] = 'Error_2_text';
        /*
        .
        .
        .
        */
        $data['error']['error_n'] = 'Error_n_text';
        echo(json_encode($data));  // <<<< just $data here
    }
?>

<body>
    <div class="ssss"></div>
</body>
<script>
    $.ajax({
        url: "http://localhost/path/to/above/file",
        method: "POST",
        dataType : 'json',  //<<<<< here
        data: {
            submit: 'yes',
            form_data_0: 'form_text',
            form_data_1: 'form_text',
            form_data_2: 'form_text'
        },
        success: function(data){
            // Code to check if errors were present
            if (data.error) {   //<<<<< here
                $.each(data.error, function(key, error) {
                    // Display each error into a modal
                    $("div#ssss").append('<div id="dmessage_' + key + '" class = "modal" style="display:block"><p id = "pmessage_' + key + '">' + error + '</p></div>');
                });
            }else{
               $("div#ssss").html('');
            }
        }
    });
</script>

Using $.each loop to create multiple divs, not working

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Answer