Getting the errors:
Warning: mysqli_select_db() expects exactly 2 parameters, 1 given in C:UsersrootDesktopWebServerhtdocstest.php on line 9
Warning: mysqli_query() expects at least 2 parameters, 1 given in C:UsersrootDesktopWebServerhtdocstest.php on line 13
Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, null given in C:UsersrootDesktopWebServerhtdocstest.php on line 39
I can’t notice the problem, kind of new to this, can anyone see the problem?
Any help is very appreciated!
<?php //make connection mysqli_connect('localhost', 'root', ''); //select db mysqli_select_db('altislife-dev'); $sql="SELECT * FROM players"; $records=mysqli_query($sql); ?> <html> <head> <title>Data</title> </head> <body> <table width="600" border="1" cellpadding="1" cellspacing="1"> <tr> <th>uid</th> <th>name</th> <th>aliases</th> <th>playerid</th> <th>cash</th> <th>bankacc</th> <th>coplevel</th> <tr> <?php while($players=mysqli_fetch_assoc($records)) { echo "<tr>"; echo "<td>".$players['uid']."</td>"; echo "<td>".$players['name']."</td>"; echo "<td>".$players['aliases']."</td>"; echo "<td>".$players['playerid']."</td>"; echo "<td>".$players['cash']."</td>"; echo "<td>".$players['bankacc']."</td>"; echo "<td>".$players['coplevel']."</td>"; echo "</tr>"; } ?> </table> </body> </html>
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Answer
do the correction as below:
$conn = mysqli_connect('localhost', 'root', '');
the first thing that you have to pass connection variable in the select_db as first parameter. as below.
mysqli_select_db($conn,'altislife-dev');
also you have to pass connection variable in mysqli_query() as first parameter as given below.
$records=mysqli_query($conn,$sql);